345-f09-exam1-solutions

345-f09-exam1-solutions - ECE 345 Fall 2009 Exam I _ 100...

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Unformatted text preview: ECE 345 Fall 2009 Exam I _ 100 Points — 50 Minutes Problem Page Value Score 1 1 10 2 l 15 3 2 20 4 2 5 5 3 25 6 3 10 7 4 15 - TOTAL Instructions: 1; . Print name, PID and section number below. 2. Closed book / Closed notes 3. No programmable or graphing calculators allowed; only simple scientific calculators permitted. 4. Work only in the spaces provided; show all work. 5. Keep yourueyes on your own work. Any and all cheating will be dealt with to the full extent of University policy. 6. Turn off and stow any cell phones, PDA's, etc. 7. Express all answers in proper engineering notation. mWWW PE): E I SECTEON N04 1. (10) Find the minimum value for R that can be used Without exceeding a 1/2 Watt rating for the resistor. 3. (20) Use the current divider rule to find currents i1 and i2. M est-‘2‘“ («092: .02, 2" «game @+3 . 30 {i”"c,ta/\0k if). w VKVB My, “gaffes/4; “thew ‘ v : {Q Gag-adj ‘ ‘7' m0 058’ gawk Azmgg fig>$ ’ngyzg (CREE/k Wmf? ’7: 20M”: *5 #Qm f? (KCEQB 4. (5) Use KCL to determine the unknown current i. ' 92A 5. (25) Find Reg, is and detelmjne the power absorbed by the voltage source. equivalent resistance of 4 Q. Find R. fol/HO/IR =4 «ta—$.22va @9311; 3W< I 8R 3 32 WW @ W =3 32;.» we? R :2 8R “0 PM“! 7. (15) Consider the circuit below: c. I . “Q £21); A (3) Find the entrant i. _ V’ g 6?: 9+:2;+'2.8 AM ~‘ B (4) Find Vow. I I \yéw a (12.27:) (m) w 6, 3.5%; C. (8) Find the power delivered by the source by at least two different methods. (D ?:4f2 == (i0)(:227> : 2.27W 2, y , @ P 3 AZ'RQi a: (:22?) 4”»: W W105+ ~ @4an F a“? v w £623 :3 ’1 m} Ea? 2 ‘7 gar {vi/35‘} {mafia ...
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This note was uploaded on 10/24/2010 for the course ECE ECE 345 taught by Professor Shanblatt during the Fall '09 term at Michigan State University.

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345-f09-exam1-solutions - ECE 345 Fall 2009 Exam I _ 100...

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