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**Unformatted text preview: **a) y[n] + 0.5y[n-1] = 2x[n-1]; x[n] = [n], y[-1] = 0 b) y[n] + 2y[n-1] = 2x[n-1]; x[n] = [n], y[-1] = 0 c) y[n] + 1.2y[n-1] + 0.32y[n-2] = x[n]-x[n-1]; x[n] = u[n], y[-2] = 1, y[-1]=2...

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