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# solution3_pdf - So(dds785 HW04 Radin(54915 This print-out...

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So (dds785) – HW04 – Radin – (54915) 1 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points A Calculus student begins walking in a straight line from the RLM building towards the PCL Library. After t minutes his velocity v = v ( t ) is given (in multiples of 10 yards per minute) by the function whose graph is -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 2 4 6 8 10 2 2 4 6 2 t v How far is the student from the RLM build- ing at time t = 5? 1. dist = 55 yards 2. dist = 65 yards 3. dist = 35 yards 4. dist = 45 yards correct 5. dist = 85 yards Explanation: The student is walking towards the PCL Library whenever v ( t ) > 0 and towards RLM whenever v ( t ) < 0. The distance he has walked is given by 10 times the area between the graph of v and the t axis since 1 unit is equivalent to 10 yards. Now at t = 5 this area is 4 . 5 units, so the student has walked a distance of 45 yards. 002 (part 2 of 4) 10.0 points How far is the student from the RLM build- ing at time t = 7? 1. dist = 95 yards 2. dist = 145 yards 3. dist = 125 yards 4. dist = 105 yards correct 5. dist = 115 yards Explanation: The distance the student has walked is given by the area between the graph of v and the t axis. Now at t = 7 this area is 10 . 5 units, so the student has walked a distance of 105 yards. 003 (part 3 of 4) 10.0 points What is the total distance walked by the student from time t = 0 to t = 10? 1. dist = 155 yards 2. dist = 165 yards correct 3. dist = 195 yards 4. dist = 145 yards 5. dist = 175 yards Explanation: The distance the student has walked is given by the area between the graph of v and the t axis. Now at t = 10 this area is 16 . 5 units (area is always positive remember), so the student has walked a distance of 165 yards. 004 (part 4 of 4) 10.0 points How far is the student from the RLM build- ing when he turns back? 1. dist = 175 yards 2. dist = 145 yards

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So (dds785) – HW04 – Radin – (54915) 2 3. dist = 125 yards 4. dist = 195 yards 5. dist = 155 yards correct Explanation: The student will turn back when his veloc- ity changes from postive to negative, i.e. , at t = 9. At this time he is 155 yards from the RLM building. keywords: distance, time, graph, velocity, area 005 10.0 points Determine the indefinite integral I = integraldisplay 2 + 4 x x dx . 1. I = 4 x 1 / 2 + 8 3 x 3 / 2 + C correct 2. I = 2 x 1 / 2 + 8 3 x 3 / 2 + C 3. I = 4 x 1 / 2 8 3 x 3 / 2 + C 4. I = 2 x 1 / 2 8 3 x 3 / 2 + C 5. I = 2 x 1 / 2 4 3 x 3 / 2 + C 6. I = 4 x 1 / 2 + 4 3 x 3 / 2 + C Explanation: After division we see that 2 + 4 x x = 2 x + 4 x = 2 x 1 / 2 + 4 x 1 / 2 .
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solution3_pdf - So(dds785 HW04 Radin(54915 This print-out...

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