e1 - if(carry==1) { z.data[i]=1; z.top=i; } return z; }...

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#include<stdio.h> #include<conio.h> #include<math.h> struct stack {  int data[10];  int top; }; void dectobin(int z,struct stack *p) {  int x;  x=z;  p->top=-1;  do  {   (p->top)++;   p->data[p->top]=x%2;   x=x/2;  }while(x>0); } void display(struct stack *p) {  int z;  z=p->top;  while(z>=0)  {   printf("%d",p->data[z]);   z--;  } } int bintodec(struct stack *p) {  int i,x=0;  for(i=0;i<=p->top;i++)
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 {   x=x+(p->data[i]*pow(2,i));  }  return x; } struct stack add(struct stack *p,struct stack *q) {  struct stack z;  int carry=0,i,max,t1,t2;  z.top=-1;  if(p->top>q->top)  max=p->top;  else  max=q->top;  for(i=0;i<=max;i++)  {   if(i<=p->top)   t1=p->data[i];   else   t1=0;   if(i<=q->top)   t2=q->data[i];   else   t2=0;   z.data[i]=(t1+t2+carry)%2;   (z.top)++;   if(t1+t2+carry<2)   carry=0;
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  else   carry=1;  }
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Unformatted text preview: if(carry==1) { z.data[i]=1; z.top=i; } return z; } void main() { int a,b,c,x; struct stack a1,b1,c1; clrscr(); printf(&quot;Enter the two decimal nos&quot;); scanf(&quot;%d%d&quot;,&amp;a,&amp;b); dectobin(a,&amp;a1); dectobin(b,&amp;b1); printf(&quot;The first no in binary is &quot;); display(&amp;a1); printf(&quot;\nThe second no in binary is &quot;); display(&amp;b1); c1=add(&amp;a1,&amp;b1); printf(&quot;\nThe Addition of the Binary nos is&quot;); display(&amp;c1); c=bintodec(&amp;c1); printf(&quot;\nThe addition of the decimal nos is %d&quot;,c); getch(); } OUTPUT: Enter the two decimal nos 512 511 The first no in binary is 1000000000 The second no in binary is 111111111 The Addition of the Binary nos is1111111111 The addition of the decimal nos is 1023...
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e1 - if(carry==1) { z.data[i]=1; z.top=i; } return z; }...

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