# booths - #include<stdio.h> DEEPAK...

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Unformatted text preview: #include<stdio.h> DEEPAK AGRAWAL #include<conio.h> SE CMPN A #include<math.h> ROLL NO 03 BOOTHS ALGORITM void main() { int b[8],a[8],q[8],q1,i=-1,j,x,y,r,u,k,carry,s,borrow; clrscr(); printf("ENTER TWO NO\n"); scanf("%d %d",&x,&y); r=x; u=y; if(x<0) x=x*-1; if(y<0) y=y*-1; while(x!=0||y!=0) { i++; b[i]=x%2; x=x/2; q[i]=y%2; y=y/2; } while(i<=3) { i++; b[i]=0; q[i]=0; } if(r<0) { for(j=0;j<=i;j++) { if(b[j]==1) { for(s=j+1;s<=i;s++) { if(b[s]==1) b[s]=0; else b[s]=1; } break; } } } if(u<0) { for(j=0;j<=i;j++) { if(q[j]==1) { for(s=j+1;s<=i;s++) { if(q[s]==1) q[s]=0; else q[s]=1; } break; } } } printf("\nFirst no.is "); for(j=i;j>=0;j--) printf("%d",b[j]); printf("\nSecond no.is "); for(j=i;j>=0;j--) printf("%d",q[j]); for(j=0;j<=i;j++ ) a[j]=0; q1=0; printf("\n\nThe calulation is \n\n"); for(k=0;k<=i;k++) { carry=0; if(q1==0 && q[0]==1) { borrow=0; for(j=0;j<=i;j++) { a[j]=a[j]-b[j]-borrow; if(a[j]==-1) { a[j]=1; borrow=1; } else { if(a[j]==-2) { a [j]=0; borrow=1; } else borrow=0; } } } else { if(q1==1&&q[0]==0) { for(j=0;j<=i;j++) { a[j]=a[j]+b[j]+carry; if(a[j]==2) { a[j]=a[j]%2; carry=1; } else { if(a[j]==3) { a[j]=a[j]%2; carry=1; } else carry=0; } } } } q1=q[0]; for(j=0;j<i;j++) q[j]=q[j+1]; q[i]=a[0]; for(j=0;j<i;j++) a[j]=a[j+1]; printf("\n"); for(j=i;j>=0;j--) printf("%d",a[j]); printf(" "); for(j=i;j>=0;j--) printf("%d",q[j]); printf(" "); printf("%d",q1); } getch(); } /***************OUTPUT************** ENTER TWO NO-5 6 First no.is 11011 Second no.is 00110 The calulation is 00000 00011 0 00010 10001 1 00001 01000 1 11110 00100 0 11111 00010 0 */ #include<stdio.h>#include<stdio....
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## This note was uploaded on 10/25/2010 for the course CMPN SEM4 taught by Professor Thakur during the Spring '07 term at University of Mumbai.

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booths - #include<stdio.h> DEEPAK...

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