This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: C that makes the equation true. (Sea level is 3,963 miles from the center of the Earth.) C= wr^2 = 100 x 3963^2 = 1570536900 c. Use the value of C you found in the previous question to determine how much the object would weigh in i. Death Valley (282 feet below sea level). R= 3963 (252/5280) = 3962.946591 miles ii. the top of Mount McKinley (20,320 feet above sea level). (20,320 x 5280) + 3963= 3966.869318 miles 2. The equation h D 2 . 1 = gives the distance, D , in miles that a person can see to the horizon from a height, h , in feet. a. Solve this equation for h . D=1.2nh nh= D/ 1.2 h=(D/1.2)^2 b. Long’s Peak in Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer. H=14255 D= 1.2n14255=143.273 miles MAT/117 Yes, you can easily see Cheynne Wyoming, becaue 89 < 143.273 MAT/117...
View
Full
Document
This note was uploaded on 10/25/2010 for the course AXIA COLLE Mat 117 taught by Professor Herman during the Spring '10 term at University of Phoenix.
 Spring '10
 Herman

Click to edit the document details