HW-Ch5 - 5 − 1(c ) : Given σ x = −6 kpsi, σ y = −10...

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Unformatted text preview: 5 − 1(c ) : Given σ x = −6 kpsi, σ y = −10 kpsi, τ xy = −5 kpsi τ xy = Pure shear from torsion σ x = (σ x )bending + (σ x ) P A (σ x )bending Mc M ( d ) 32M 2 = = = , 3 πd 4 ) I πd ( 64 (σ x ) P = P 4P = A πd 2 τ xy 16T = πd 3 τ x y = Pure shear from torsion+shear from Bending B σ x = (σ x )P , Because the element is at the N.A P 4P (σ x ) P = = A πd 2 16T 4V (τ xy )T = , (τ xy ) M = 3A πd 3 ...
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This note was uploaded on 10/25/2010 for the course MECHINCAL 2010 taught by Professor علاءحجازي during the Spring '10 term at Hashemite University.

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HW-Ch5 - 5 − 1(c ) : Given σ x = −6 kpsi, σ y = −10...

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