PracticeQuestions2Answers

PracticeQuestions2Answers - Practice Questions 2 Answers 1....

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Practice Questions 2 Answers 1. a. C b. A 2. C 3. a. P (A) = 0.17 + 0.13 + 0.04 = 0.34 b. No, since P ( A U B ) S . c. P ( A ) =1 – P( A ) = 1 – 0.34 = 0.66 d. P ( A I B ) = 0, since A and B are mutually exclusive events. 4. a. Event S: Supports US policy in Iraq, Event F: Female. P ( S ) = 0.62, P ( F ) = 0.53 and P ( S | F ) = 0.46. Therefore, P ( F I S ) = P ( S | F ) P ( F ) = (0.46)(0.53) = 0.2438 b. P ( F | S ) = P ( F S I ) / P ( S ) = 0.2862 / 0.38 = 0.753 and P ( F ) = 0.53 Since P ( F | S ) P ( F ), the events “ does not support US policy in Iraq” and “female” are not statistically independent. c. Event M: Male P ( M ) = 1 – P ( F ) = 1 – 053 = 0.47 d. ANSWER: P (Does not support US policy in Iraq) = 1 – P ( S ) = 1 – 0.62 = 0.38 US Policy in Iraq Gender e. P ( F ) = P ( F I S ) + P ( F S I ) 0.53 = 0.2438 + P ( F S I ). Hence, P ( F S I ) = 0.2862. f. P ( S ) = P ( S I F ) + P ( S I M ) 0.62 = 0.2438 + P ( S I M ). Hence, P ( S I M ) = 0.3762. g. P ( M ) = P ( M I S ) + P ( M I S ) 0.47 = 0.3762 + P ( M I S ). Hence, P ( M I S ) = 0.0938. Support Doesn’t Support Row Total Female 0.2438 0.2862 0.53 Male 0.3762 0.0938 0.47 Column Total 0.62 0.38 1.00
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h. P ( F | S ) = P ( F I S ) / P ( S ) = 0.2438 / 0.62 = 0.393
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PracticeQuestions2Answers - Practice Questions 2 Answers 1....

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