PracticeQuestions5Answers

- 29 0.1149 20 e-= 2.3 e-= 0.1 P ˆ P>0.20 = P[Z>(0.20 – 0.1 0.09 25 = P Z>1.67 = 0.0475 38 For the Poisson distribution = E X = Var X =

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Practice Questions 5 Answers 1. C 2. B 3. D 4. B 5. B 6. A 7. C 8. B 9. D 10. A 11. B 12. D 13. C 14. A 15. C 16. B 17. B 18. B 19. D 20. A 21. C 22. C 23. D 24. D 25. 10, 2.4, 12 n μ σ = = = ( 11) P X = P ( Z > 1.44) = 1 – 0.9251 = 0.0749 26. 10, 2.4, 12 n = = = 10 10 ( ) 0.85 ( ) 0.85 1.04 10.721 0.6928 2.4 / 12 a a P X a P Z a - - < = < = = = 27. 300 298 2 2 ( 300) 0.20 ( ) 0.20 ( ) 0.20 0.84 15.4 15.4 15.4 / 41.84 42 n n P X P Z P Z n n - = = = = - = 28. P (4.0< X <4.2) = P ( Z < 0.24) – P ( Z < -0.24) = 0.5948 - 0.4052 = 0.1896 29. ( 29 4.1 4.1 0.95 .95 0.411 1.3/ 10 4.1 1.645 3.42 minutes 0.411 a a P X a P Z P Z a a - - = = = - = - =
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30. P = 0.15, n = 100 E ( ˆ P ) = P = 0.15 Var( ˆ P ) = P (1- P ) / n = (0.15)(0.85)/100 = 0.001275. Hence, σ = 0.0357 P ( ˆ P >0.18) = P ( Z > 0.84) = 0.2005 31. P = 0.621 32. 2 β = P (1- P ) / n = (0.621)(0.379)/100 = 0.00235 33. ˆ 0.00235 P = = 0.0485 34. P ( ˆ P > 0.60) = P ( Z >- 0.43) = 0.6664 35. P ( 2 s > 0.5)= ( 29 ( 29 ( 29 2 2 1 29 0.5 0.3 n s P - = P ( 2 χ >48.33) < 0.01 36. ( 29 2 2 2 1 29 ( ) 0.10 0.10 0.3 n s k P s k P - < = < = ( 29 2 96.67 0.10 P k < = 96.67 19.768 k = 0.2045 k = 37. λ = 1 / 8.7 = 0.1149 P = P (one game with no score in first 20 minutes) =
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Unformatted text preview: ( 29 0.1149 20 e-= 2.3 e-= 0.1 P ( ˆ P >0.20) = P[Z >(0.20 – 0.1)/ 0.09/ 25 ] = P ( Z >1.67) = 0.0475 38. For the Poisson distribution, = E ( X ) = Var ( X ). = = 4.2 2.05 = . P( X > 5) = P [ Z > (5 - 4.2) / (2.05 / 40 ] = P ( Z > 2.46) = 0.0069 39. 1742 and 132 μ = = P ( X < 1700) = 1700 1742 132/ 70 P Z- < = P ( Z < -2.66) = 0.0039 40. P [ X > k ) = 0.23 = 1742 1742 15.777 132/ 70 K K P Z P Z-- = ⇒ 1742 15.777 K-= 0.74 ⇒ K = $1,753.67. 41. 15, 6.40, 1.7 n x = = = ( 29 6.40 6.40 6.40 0.36 0.36 0.36 0.4389 1.7 15 P x P Z P Z-- ≥ = ⇒ ≥ = ⇒ ≥ = 6.40 0.36 6.242 0.4389 μ-⇒ = ⇒ =...
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This note was uploaded on 10/25/2010 for the course ECO 329 taught by Professor K during the Spring '08 term at University of Texas at Austin.

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- 29 0.1149 20 e-= 2.3 e-= 0.1 P ˆ P>0.20 = P[Z>(0.20 – 0.1 0.09 25 = P Z>1.67 = 0.0475 38 For the Poisson distribution = E X = Var X =

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