H04_Equilibrium 1

H04_Equilibrium 1 - krohn(tek335 H04 Equilibrium 1...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: krohn (tek335) H04: Equilibrium 1 Mccord (52445) 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points An equilibrium in which processes occur con- tinuously, with NO NET change, is called 1. homogeneous equilibrium. 2. dynamic equilibrium. correct 3. static equilibrium. 4. heterogeneous equilibrium. Explanation: For a system at dynamic equilibrium, al- though the concentrations of the components do not change, the processes continue to oc- cur in the foward and reverse directions at the same rate. 002 10.0 points Explain why equilibium constants are dimen- sionless. 1. They are not really dimensionless but we must treat them as such in order to be able to take ln K in the expression G =- RT ln K . 2. The statement is not true. Equilibrium constants have units that involve some multi- ple of atmospheres or moles per liter. 3. They are dimensionless because concen- trations and pressures have no units. 4. They are dimensionless because the pres- sures or concentrations we put in are all for the substances in their standard states. 5. Every concentration or pressure that en- ters into K c or K p is really divided by the cor- responding concentration or pressure of the substance in its standard state. correct Explanation: The amount of each component is in terms of activity, which is the measured amount (concentration, pressure) divided by the amount of that component in its standard state in that unit. The units in the numera- tor and denominator are identical and cancel out. 003 10.0 points The expression for K c for the reaction at equi- librium is 4 NH 3 (g) + 5 O 2 (g) 4 NO(g) + 6 H 2 O(g) 1. [NH 3 ] 4 [O 2 ] 5 2. [NO] 4 [H 2 O ] 6 3. [NO] 4 [H 2 O] 6 [NH 3 ] 4 [O 2 ] 5 correct 4. [NH 3 ] 4 [O 2 ] 5 [NO] 4 [H 2 O] 6 Explanation: The equation must be written with the ap- propriate formula and correctly balanced. K c is the equilibrium constant for species in so- lution and equals the mathematical product of the concentrations of the chemical prod- ucts, divided by the mathematical product of...
View Full Document

This note was uploaded on 10/25/2010 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas.

Page1 / 5

H04_Equilibrium 1 - krohn(tek335 H04 Equilibrium 1...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online