12_110

# 12_110 - • The projectile equation for horizontal motion...

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Problem 12-110 (page 54) COMPLETION OF PROBLEM 12-110 The trajectory equation is y ( x ) = a ( x ! x 0 ) 2 + b ( x ! x 0 ) + y 0 where a = ! g 2 v 2 0 cos 2 " 0 b = tan ! 0 When ! 0 = 25 ! , ( x 0 , y 0 ) = (0, 4) ft and ( x , y ) = (80, ! 60) ft , it follows that : ! 60 = ! 9.81(80) 2 2 v 0 2 cos 2 25 o + 80tan25 o + 4 solving which using Solver gives v 0 = 19.4 m/s
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Unformatted text preview: . • The projectile equation for horizontal motion is x ( t ) = x + v x t = x + v t cos It follows that 80 = (19.4cos25 o ) t so t = 4.54 s ....
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