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HW6 - Lin(cgl286 Homework 6 Lyon(52370 This print-out...

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Lin (cgl286) – Homework 6 – Lyon – (52370) 1 This print-out should have 48 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. This HW assignment is due Tuesday, March 10, by 11PM. 001 10.0 points What is the formal charge on the Xenon atom (Xe) in XeF 2 ? 1. 2 2. - 4 3. - 2 4. 6 5. 0 correct Explanation: 002 10.0 points Based on formal charge considerations, which of the following is a better Lewis struc- ture for phosphate ion PO 4 3 ? I) P O O O O II) P O O O O 1. Both are correct 2. Neither is correct 3. II 4. I correct Explanation: 003 10.0 points A free radical is ? chemical species with ? . 1. an unstable; an unpaired electron cor- rect 2. a low energy; an unpaired electron 3. a reactive; a full octet of electrons 4. a stable; a lone pair of electrons Explanation: Free radicals are very energetic and reactive particles that have an unpaired electron. 004 10.0 points The valence shell electron pair repulsion the- ory (VSEPR) is used to 1. predict the number of multiple bonds in a molecule. 2. predict the bonding pattern in molecules. 3. predict the electronegativity of atoms. 4. predict the three dimensional structure of molecules. correct Explanation: 005 10.0 points Predict the bond angles for the molecular structure. Predict the bond angle at the central atom of ClO 2 . 1. 180 2. 90 3. 60 4. slightly less than 109.5 correct 5. 30
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Lin (cgl286) – Homework 6 – Lyon – (52370) 2 6. slightly less than 120 Explanation: Cl O O 006 10.0 points Which of the following molecules is not lin- ear? 1. None of the answers is correct. 2. N 2 3. CO 2 4. O 3 correct 5. Cl 2 Explanation: O O O is bent. 007 10.0 points The molecular formula for phosgene is COCl 2 , with carbon being the central atom. The elec- tronic arrangement is ? and the molecular shape is ? . 1. tetrahedral; tetrahedral 2. trigonal planar; trigonal planar correct 3. trigonal planar; angular 4. trigonal bipyramidal; T-shaped 5. tetrahedral; trigonal planar Explanation: 008 10.0 points Choose the species that is incorrectly matched with electronic geometry about the central atom. 1. ClO 4 : tetrahedral 2. NO 2 : trigonal planar 3. SO 2 3 : pyramidal correct 4. ClO 3 : tetrahedral 5. BrO 4 : tetrahedral Explanation: 009 10.0 points NF 2 has (2, 3, 4) regions of high electron density and (2, 4, 6) bonded electrons. 1. 2; 2 2. 4; 6 3. 3; 6 4. 2; 6 5. 4; 2 6. 3; 4 7. 4; 4 correct 8. 2; 4 9. 3; 2 Explanation: N = 8 × 3 = 25 A = 5 + (7 × 2) + 1 = 20 S = 24 - 20 = 4 First, draw the molecule. The number of regions of HED equals the number of bonds and the number of lone pairs. There are 4 shared, or bonded electrons, giving 2 regions of HED. The 2 F atoms have an octet. This means that 16 of the 20 available electrons are accounted for, leaving 4 electrons to be placed on the N atom as 2 lone pairs. Since there are 2 lone pairs, 2 bonds, that gives a total of 4 regions of HED.
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