giang (dvg247) – Homework 2 – Sutclife – (50965)
1
This printout should have 20 questions.
Multiplechoice questions may continue on
the next column or page – Fnd all choices
be±ore answering.
This assignment covers the remaining ma
terial that will be in the Frst exam.
001
10.0 points
You are caught in a radar trap and hope to
show that the speed measured by the radar
gun is in error due to the uncertainty prin
ciple. I± you assume that the uncertainty in
your position is large, say about 10 m, and
that the car has a mass o± 2150 kg, what is
the uncertainty in the velocity?
1.
5
.
0
×
10

38
m
/
s
2.
4
×
10
38
m
/
s
3.
1
×
10

39
m
/
s
4.
1
×
10
33
m
5.
2
.
5
×
10

39
m
/
s
correct
Explanation:
Δ
x
=10m
m
=2150kg
Δ
v
=
¯
h
2
m
Δ
x
=
1
.
055
×
10

34
J
·
s
2(2150kg)(10m)
=2
.
45349
×
10

39
m
/
s
002
10.0 points
In a onedimensional particle in a box, ±or
n
=
7, how many WHOLE wavelengths equals the
size o± the box?
1.
7
2.
3.5
correct
3.
6
4.
14
Explanation:
²or
n
=7thewave±unctionwou
ldbe
x
=0
x
=
L
003
10.0 points
An electron is conFned in a 1dimensional box
3nmlong
. Ca
lcu
latetheenergyrequ
ired±or
it to move ±rom the
n
=8tothe
n
=9energy
level.
1.
2
.
133
×
10

14
J
2.
6
.
694
×
10

21
J
3.
3
.
414
×
10

28
J
4.
2
.
133
×
10

19
J
5.
1
.
138
×
10

19
J
correct
6.
5
.
238
×
10

19
J
7.
1
.
717
×
10

14
J
Explanation:
n
1
=8
n
2
=9
h
=6
.
626
×
10

34
J
·
s
L
=13
×
10

9
m
m
.
109
×
10

31
kg
Δ
E
=
E
n
2

E
n
1
=
(
n
2
2

n
2
1
)
h
2
8
mL
2
=
(9
2

8
2
)(6
.
626
×
10

34
J
·
s)
2
8(9
.
109
×
10

31
kg) (3
×
10

9
m)
2
=1
.
13802
×
10

19
J
004
10.0 points
Aquantummechanicalparticleinaboxinits
ground state is most likely to be ±ound
1.
in the middle o± the box.
correct
2.
at both edges o± the box.
3.
is equally likely to be ±ound at all positions
in the box.
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View Full Documentgiang (dvg247) – Homework 2 – Sutclife – (50965)
2
4.
at the very edge oF the box.
5.
is equally likely to be Found at all positions
except the very center oF the box.
Explanation:
The ground state is Ψ
1
which has maximum
probability in the middle oF the box.
005
10.0 points
±or
n
=7and
±
=4,whatis
m
±
?
1.

4,

3,

2,

1, 0, +1, +2, +3, +4
correct
2.
0, 1, 2, 3, 4
3.
0, 1, 2, 3
4.
9
5.
18
Explanation:
006
10.0 points
Which oF the Following sets oF quantum num
bers is allowed For an atomic orbital?
1.
n
=1,
±
m
±
m
s
=1
2.
n
=3,
±
m
±
=2,
m
s
=

1
2
3.
n
±
=0,
m
±
m
s
=
1
2
4.
n
±
m
±
m
s
=
1
2
5.
n
±
m
±
m
s
=

1
2
correct
Explanation:
007
10.0 points
In an atom, the maximum number oF electrons
having the quantum numbers
n
=5and
±
=3
is
1.
14.
correct
2.
50.
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 Fall '07
 Fakhreddine/Lyon
 Chemistry, Atom, Electrons, Atomic orbital, Giang

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