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Unformatted text preview: 27 km/h ? P(54 km/h)/P(27 km/h) = ? A. 1 B. 2 C. 4 D. 8 E. 16 Power and Energy in Cycling Assume P cyclist Drag force velocity (P = Dv) P cyclist = 1/2 C A v 2 v = 1/2 C A v 3 Assume C~ 0.4, = 1.2 kg/m 3 , A~0.7 m 2 Assume human body ~ 25% efficient in converting food energy into mechanical energy. 1 Cal =4.2 J, 1 food Calorie =1 kCal = 4,200 J Prof. Liepe: v ~ 8 m/s (17 mi/h) P ~ 86 W (~0.12 hp) Burns ~ 344 W, 1.24 MJ/hour, 295 kCal/hour Professional distance cyclist: v ~ 14 m/s (~30 mi/h) P ~ 460 W (~0.6 hp) Burns ~1.8 kW, 6.6 MJ/hour, 1580 kCal/hour Professional sprint cyclist: v ~ 20 m/s (~45 mi/h) P ~ 1340 W (~1.8 hp) Burns ~ 5.4 kW, 19 MJ/hour, 4600 kCal/hour Average daily food energy intake for Tour de France Cyclists: ~10,000 kCal/ day (~7 lb of uncooked pasta)...
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This note was uploaded on 10/27/2010 for the course PHYS 2207 at Cornell University (Engineering School).
 '07
 LIEPE, M
 Physics, Friction, Power, Work

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