notes1013 - Charley Crissman Math 55 Discussion Notes...

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Charley Crissman Math 55 Discussion Notes October 13th, 2010 Permutations and Combinations Question: Recall that a poker hand consists of 5 cards from a standard 52-card deck. How many ways are there to get a: 1. four-of-a-kind? 2. two-of-a-kind? 3. hand with no pairs? 4. flush? (All cards the same suit) 5. straight? (A straight is five cards with consecutive ranks, but can be of any suit) 6. straight flush? (combine the above two) Four-of-a-Kind: To get a four-of-a-kind, we need all four cards of a single denomination, plus one additional card. There are 13 denominations, and once we have chosen our denomination, there are 48 remaining cards not of that denomination which we can take as our additional card. Hence our solution is: 13 · 48 = 624 Two-of-a-Kind: There are several ways to compute this. Here is one method: Choose a denomination for our pair (13 possible choices), then choose two cards of that denomination ( ( 4 2 ) = 6 choices). Now, to choose the remaining three cards, we can choose their denominations (
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This note was uploaded on 10/27/2010 for the course MATH 54257 taught by Professor Hald,oh during the Spring '10 term at University of California, Berkeley.

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