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11. ENG 282 ch5 b X

# 11. ENG 282 ch5 b X - GeorgeHaines,Instructor Chapter5.65.7...

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BASIC ELECTRIC CIRCUITS BASIC ELECTRIC CIRCUITS George Haines, Instructor George Haines, Instructor Pima Community College Chapter 5.6-5.7

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Chapter 5  Chapter 5  The Operational Amplifier Today The Operational Amplifier Today 5.6 The Difference-Amplifier Circuit 5.7 A More Realistic Model for the  Operational Amplifier
http://www.pearsonhighered.com/nilsson/ Video Example Solutions

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5.6 The Difference-Amplifier Circuit 5.6 The Difference-Amplifier Circuit NVA at v n : (v n -v a )/R a + (v n -v o )/R b + i in = 0 The op amp is ideal, therefore: i n = i p = 0 and v n = v p = [R d /(R c + R d )]v b v o = [R d (R a + R b )v b ]/(R a (R c + R d )) – (R b /R a )v a I.e. v o is proportional to the difference between a scaled v a and v b . In general the scaling factor for v b is not the same as v a . However, the scaling factors can be made the same by setting R a /R b = R c /R d . Then: v o = (R b /R a )(v b – v a ).
Assessing Objective 2 a) If v b = 4.0 V, what range of values for v a will result in linear operation?

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11. ENG 282 ch5 b X - GeorgeHaines,Instructor Chapter5.65.7...

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