answersbookchapter3

answersbookchapter3 - Chapter 3 1 10 36 P1(366 1 = 1/3 6 9...

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Chapter 3. P1 10 · 1 36 (36 - 6) · 1 36 = 1 / 3 P5 6 2 6 + 9 2 · 9 2 4 + 9 2 = 6 91 P7 For simplicity, do not consider twins. From the four equally likely possibilities (he, sister), (he, brother), (sister, he), (brother, he) (where the elder child is listed first) the last one should not be regarded because the elder brother becomes the king. From the three remaining cases, in two he has a sister. So the answer is 2/3. P8 1/2 P10 13 - 2 52 - 2 . This can be seen directly or from the formula of conditional proba- bility: P (the first is spade | the second and the third are spades) = P ( all three are spades ) P ( the second and the third are spades ) = 13 3 / 52 3 13 2 / 52 2 = 11 50 P17 (a) P ( DC ) = P ( D ) · P ( C | D ) = . 36 · . 22 = . 0792 (b) P ( D | C ) = P ( DC ) P ( C ) = . 0792 . 3 = . 264 P18 (d) P ( V ) = P ( V I ) + P ( V L ) + P ( V C ) = P ( I
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This note was uploaded on 10/27/2010 for the course MATH 351 taught by Professor Moumen,f during the Spring '08 term at George Mason.

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answersbookchapter3 - Chapter 3 1 10 36 P1(366 1 = 1/3 6 9...

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