# Hw2 - 1.4.11 Without the missing c there are 50 individuals 8 of whom have brown hair and 20 of whom have blue eyes To satisfy the condition we

This preview shows pages 1–2. Sign up to view the full content.

1.4.11. Without the missing c, there are 50 individuals, 8 of whom have brown hair and 20 of whom have blue eyes. To satisfy the condition, we must have .Rr+ P[brown hair] : ;# = P[brown hair I blue eyes] ' bu+t =r 20*z' Therefore (8 +r)(20 *r) : r(50 + r) + 160 *28s :b0c + 160 : 22r. There is no integer value of r satisfying the last equation. 3g / Nu, z I I 1.4.13. (a) PlXz: rl :p(l -p)+ (r-p).L:L-p2; PlX2:3] :p'p:p2. (b) PlX3 :11 : (1 - p)(1 - pX1 - p) : (1 - p)3; P[&:3] :p(l-p)(i -p)+ (1-p)p(1 -p)+ (1-pXt-p)p :3p(r - p)2; PlX3 : 5l : p. p(l - p) + p(I - p)p + (L - p)p - p : 3p2 (t - p); P[X3:7]:p.p-p:p3. 1.4.15. Pflyingltest says lie] /ret P(xr= l lx,'a) = l,,ra{y (-' o*C,r.--/.z 4E u4/tM/ 49{' f)r/r, f(n t h) = : _ (.80)(.50) (.80)(.50) + (.10)(.50) _ (.80) _pro - (.80) + ('10) - "t "' L.4.L7. We assume in this problem that ace counts as 11 for the dealer. Of the 4? remaining cards, there are four each of ranks 2, 4, 6,7, 9, and ace, there are eleven face cards, and there are three each

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 10/27/2010 for the course MATH 351 taught by Professor Moumen,f during the Spring '08 term at George Mason.

### Page1 / 3

Hw2 - 1.4.11 Without the missing c there are 50 individuals 8 of whom have brown hair and 20 of whom have blue eyes To satisfy the condition we

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online