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Unformatted text preview: f Y ( y ). (Note: this was done in problem 4 of the first midterm. This part of the question is a rehash.) To find the marginal of Y , integrate out X Then Problem 3 Median = 0, Lower Quartile = 0, Upper Quartile = 16.5 The regression function of Y on X is another name for E ( Y  X ). From the formula given in the hint so the regression function is Problem 4 Median = 19, Lower Quartile = 9, Upper Quartile = 20 (a) (b) Problem 5 Median = 11.5, Lower Quartile = 4, Upper Quartile = 16 Evaluating at zero we get If we write , then and Up: Stat 5101 Charles Geyer 19991025...
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 Spring '02
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