Section 7.4-7.5

Section 7.4-7.5 - Section 7.4 (Homework) 1. [SCalcCC2...

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Section 7.4 (Homework) 1. [SCalcCC2 7.4.02.] 5/5 points Last Response | Show Details All Responses Notes A common inhabitant of human intestines is the bacterium Escherichia coli . A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. The initial population of a culture is 60 cells. (a) Find the relative growth rate. k = 2.08 2.08 (b) Find an expression for the number of cells after t hours. P ( t ) = 60*exp((3*ln(2)*t)) 60*exp(ln(8)*t) (c) Find the number of cells after 8 hours. 1 1.00663296 billion cells (d) Find the rate of growth after 8 hours. 2.09 2.09323439424814 billion cells per hour (e) When will the population reach 20000 cells? 2.79 2.79 h 2. [SCalcCC2 7.4.06.] 5.5/5.5 points Last Response | Show Details All Responses Notes
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The table gives the population of the United States, in millions, for the years 1900 - 2000. (a) Use the exponential model and the census figures for 1900 and 1910 to predict the population in 2000. 514
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This note was uploaded on 10/28/2010 for the course MA MA 241 taught by Professor Lesliekurtz during the Spring '10 term at N.C. State.

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Section 7.4-7.5 - Section 7.4 (Homework) 1. [SCalcCC2...

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