Termo-2006-07B-Odev6-cozum - MAK 212 - TERMODNAMK (CRN:...

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MAK 212 - TERMODİNAMİK (CRN: 20662, 20664, 20667, 20669) 2006-2007 BAHAR YARIYILI ÖDEV 6-ÇÖZÜMLER 1) (a) Bu bir kararsız akış durumudur ve düzgün akışlı sistem olarak düşünülebilir. Silindir son durumda 300 kPa basınçta doymuş buhar içermektedir, silindirin içindeki son sıcaklık T 2 = T sat @ 300 kPa = 133.6°C (b) The conservation of mass- and energy equations for this uniform-flow system reduces to Kütle: ( 29 1 2 1 2 0 m m m m m m m i CV e i - = → - = - Enerji: ( 29 1 1 2 2 1 1 2 2 0 0 u m u m h m W u m u m h m h m W Q i i b CV i i e e - + - = - → - + - = - İki denklemi eşitlersek, ( 29 1 1 2 2 1 2 u m u m h m m W i b - + - - = - Ya da, ( 29 1 1 2 2 1 2 0 h m h m h m m i - + - - = Çünkü sabit hacimde genişleme ve sıkıştırma işlemlerinde W b + U 2 - U 1 = H 2 - H 1 . m 2 için çözersek, m h h h h m i i 2 1 2 1 = - - Buharın özellikleri kg / kJ . h C T MPa . P kg / kJ . h h vapor . sat kPa P kg / kJ . . . . h x h h . x kPa P i i i kPa @ g fg f 7 3167 350 5 0 3 2725 300 51 2292 8 2163 8 0 47 561 8 0 300 300 2 2 1 1 1 1 = = = = = = = × + = + = = = Yerine yazarsak, ( 29 ( 29 ( 29 kg . kg kg / kJ . . kg
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This note was uploaded on 10/28/2010 for the course MECHANICAL mak204 taught by Professor Lütfullahkuddusi during the Spring '07 term at Istanbul Technical University.

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Termo-2006-07B-Odev6-cozum - MAK 212 - TERMODNAMK (CRN:...

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