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EE302 Documents - 329 Fig 7-19(d V ′ s = I s Z ′ s =...

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Errata: Book Corrections (ISBN 978-1-934891-00-1) Last update: March 18, 2010 Page Location Item Correction 48 Exercise 2-10 I x I x = 1 . 33 A 87 Fig. 3-4 V 2 V 1 = 10 V V 3 V 2 = 10 V 120 Problem 3.16 2 A source Replace with voltage source + _ 10 V 141 Fig. 4-8 upper symbol in trangle should be + 143 Example 4-3 line 14 “Since i n = 0” Since i p = 0 143 Example 4-3 last equation v n = . . . v p = . . . 144 Fig. 4-11 + and inside triangle interchange + and 144 Fig. 4-11 i n , i p , v n , v p interchange p and n subscripts 144 First equation v p = . . . v n = . . . 174 Fig. P4.7 + and on op amp Reverse + and 233 Fig. 5-51(a) and (b) Direction of current source Reverse it (downward instead of upward) 244 Figs. P5.58 and P5.59 + and on op amp Reverse + and 276 Table 6-3 Underdamped ··· +( D 2 sin ϖ d t ) e α t ] u ( t ) ··· + D 2 sin d t ] e t u ( t ) 292 Chapter 6 Relationships ··· +( D 2 sin d t ) e t ] u ( t ) ··· + D 2 sin d t ] e t u ( t ) 297 Problem 6.43 element values R s = 3 , R 1 = 0 . 5 , R 2 = 1 , L = 2 H, and C = 2 F 298 Problem 6.50 R 3 = 20 k , R 4 = 12 k R 3 = 12 k , R 4 = 20 k
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Unformatted text preview: 329 Fig. 7-19(d) V ′ s = I s Z ′ s = ··· V ′ s = I s Z ′ 1 = ··· 330 Example 7-9 phase angle − 31 . 55 ◦ − 31 . 61 ◦ 366 Figs. P7.58, P7.59, P7.61 op amp polarities interchange + and − in triangle 374 Eq. (8.36b) average exchanged power peak exchanged power 374 Line 2 after Eq. (8.36b) the average amount the peak amount 398-99 Figs. P8.17, P8.18, P8.19 op amp polarities interchange + and − in triangle 418 Fig. 9-10(b) Horizontal scale Should be same as in (a) 429 Left column, line 4 pole zero 484 Eqs. (10.62) and (10.63) s should be bold s 494 Eq. (10.115) second term 5 s 2 + 2 587 1.9 2.948 (kC) 2.948 C 588 7.10 (e) z 5 z 5 = 5 e j 53 . 13 ◦...
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