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Unformatted text preview: . 0625 3 = 0 . 0208.) Knowing that f (1 . 5) = 0 . 3535, compare to the results you obtained and conclude. Let f ( x ) = x2 cos ( x ) 1. Proove that the equation f ( x ) = 0 admits a solution p in the interval [0 , 2 ]. 2. Use the following table to determine the Frst steps of the bisection method when starting with the x 16 2 16 3 16 4 16 5 16 6 16 7 16 8 16 f ( x )21 . 761 . 451 . 07. 62. 12 . 41 . 98 1 . 57 points 0 and 2 . You will sumarize your results in this table n a n b n p n f ( p n ) 2 1 2 3 ... ... 3....
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This note was uploaded on 10/28/2010 for the course MATH 151a taught by Professor Staff during the Spring '08 term at UCLA.
 Spring '08
 staff
 Math

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