Unformatted text preview: . 0625 3 = 0 . 0208.) Knowing that f (1 . 5) = 0 . 3535, compare to the results you obtained and conclude. Let f ( x ) = x2 cos ( x ) 1. Proove that the equation f ( x ) = 0 admits a solution p in the interval [0 , π 2 ]. 2. Use the following table to determine the Frst steps of the bisection method when starting with the x π 16 2 π 16 3 π 16 4 π 16 5 π 16 6 π 16 7 π 16 8 π 16 f ( x )21 . 761 . 451 . 07. 62. 12 . 41 . 98 1 . 57 points 0 and π 2 . You will sumarize your results in this table n a n b n p n f ( p n ) π 2 1 2 3 ... ... 3....
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 Spring '08
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 Math, Numerical Analysis, Englishlanguage films, #, UCLA MATH 151A

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