ch24-p017 - 17. First, we observe that V (x) cannot be...

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Vx k q d q d q xdx () =+ F H G I K J F H G I K J = 1 1 2 20 4 13 0 π ε and solve: x = d /4. With d = 24.0 cm, we have x = 6.00 cm. (b) Similarly, for x < 0 the separation between q 1 and a point on the x axis whose coordinate is x is given by d 1 = – x ; while the corresponding separation for q 2 is d 2 = d – x . We set Vx k q d q d q F H G I K J = + F H G I K J = 1 1 2 4 0 π to obtain x = –d /2. With d = 24.0 cm, we have x =
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This note was uploaded on 10/28/2010 for the course PHYS 219 taught by Professor Gf during the Fall '10 term at Hudson Valley Community College.

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