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18. In applying Eq. 2427, we are assuming
V
→
0 as
r
→
∞
.
All corner particles are
equidistant from the center, and since their total charge is
2
q
1
– 3
q
1
+ 2
q
1
–
q
1
= 0,
then their contribution to Eq. 2427 vanishes. The net potential is due, then, to the two
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This note was uploaded on 10/28/2010 for the course PHYS 361 taught by Professor Fr during the Fall '10 term at East MS CC.
 Fall '10
 FR
 Applied Physics, Charge

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