18. In applying Eq. 24-27, we are assuming V→0 as r→∞. All corner particles are equidistant from the center, and since their total charge is 2q1– 3q1+ 2q1– q1 = 0, then their contribution to Eq. 24-27 vanishes. The net potential is due, then, to the two
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This note was uploaded on 10/28/2010 for the course PHYS 361 taught by Professor Fr during the Fall '10 term at East MS CC.