V1= 104qdπε= 5.76×10−7 V. Thus, q1/d= 6.41×10−17 C/m. Next, we note that when q2 is located at x= 0.080 m, the net potential vanishes (V1+ V2= 0). Therefore, 2100.08 mkqkqd=+Thus, we find q2= 1(/ )(0.08 m)
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