solution7_pdf - arellano (aa39398) Homework 4 Weathers...

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Unformatted text preview: arellano (aa39398) Homework 4 Weathers (17101) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points Consider four vectors vector F 1 , vector F 2 , vector F 3 , and vector F 4 with magnitudes F 1 = 59 N, F 2 = 31 N, F 3 = 27 N, and F 4 = 45 N, 1 = 150 , 2 = 140 , 3 = 20 , and 4 = 51 , measured from the positive x axis with counterclockwise positive. What is the magnitude of the resultant vec- tor vector F = vector F 1 + vector F 2 + vector F 3 + vector F 4 ? Correct answer: 26 . 6206 N. Explanation: The x components are F x = F cos , so F 1 x = (59 N) cos(150 ) = 51 . 0955 N F 2 x = (31 N) cos( 140 ) = 23 . 7474 N F 3 x = (27 N) cos(20 ) = 25 . 3717 N F 4 x = (45 N) cos( 51 ) = 28 . 3194 N and the y components are F y = F sin , so F 1 y = (59 N) sin(150 ) = 29 . 4999 N F 2 y = (31 N) sin( 140 ) = 19 . 9264 N F 3 y = (27 N) sin(20 ) = 9 . 23455 N F 4 y = (45 N) sin( 51 ) = 34 . 9716 N . The components of the resultant vector are F x = F 1 x + F 2 x + F 3 x + F 4 x = ( 51 . 0955 N) + ( 23 . 7474 N) + (25 . 3717 N) + (28 . 3194 N) = 21 . 1518 N and F y = F 1 y + F 2 y + F 3 y + F 4 y = (29 . 4999 N) + ( 19 . 9264 N) + (9 . 23455 N) + ( 34 . 9716 N) = 16 . 1635 N , so the magnitude of the resultant vector is bardbl vector F bardbl = radicalBig F 2 x + F 2 y = radicalBig ( 21 . 1518 N) 2 + ( 16 . 1635 N) 2 = 26 . 6206 N . 002 (part 2 of 2) 10.0 points What is the direction of this resultant vec- tor vector F , within the limits of 180 and 180 as measured from the positive x axis with coun- terclockwise positive ?...
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solution7_pdf - arellano (aa39398) Homework 4 Weathers...

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