solution7_pdf

# solution7_pdf - arellano(aa39398 – Homework 4 –...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: arellano (aa39398) – Homework 4 – Weathers – (17101) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points Consider four vectors vector F 1 , vector F 2 , vector F 3 , and vector F 4 with magnitudes F 1 = 59 N, F 2 = 31 N, F 3 = 27 N, and F 4 = 45 N, θ 1 = 150 ◦ , θ 2 = − 140 ◦ , θ 3 = 20 ◦ , and θ 4 = − 51 ◦ , measured from the positive x axis with counterclockwise positive. What is the magnitude of the resultant vec- tor vector F = vector F 1 + vector F 2 + vector F 3 + vector F 4 ? Correct answer: 26 . 6206 N. Explanation: The x components are F x = F cos θ , so F 1 x = (59 N) cos(150 ◦ ) = − 51 . 0955 N F 2 x = (31 N) cos( − 140 ◦ ) = − 23 . 7474 N F 3 x = (27 N) cos(20 ◦ ) = 25 . 3717 N F 4 x = (45 N) cos( − 51 ◦ ) = 28 . 3194 N and the y components are F y = F sin θ , so F 1 y = (59 N) sin(150 ◦ ) = 29 . 4999 N F 2 y = (31 N) sin( − 140 ◦ ) = − 19 . 9264 N F 3 y = (27 N) sin(20 ◦ ) = 9 . 23455 N F 4 y = (45 N) sin( − 51 ◦ ) = − 34 . 9716 N . The components of the resultant vector are F x = F 1 x + F 2 x + F 3 x + F 4 x = ( − 51 . 0955 N) + ( − 23 . 7474 N) + (25 . 3717 N) + (28 . 3194 N) = − 21 . 1518 N and F y = F 1 y + F 2 y + F 3 y + F 4 y = (29 . 4999 N) + ( − 19 . 9264 N) + (9 . 23455 N) + ( − 34 . 9716 N) = − 16 . 1635 N , so the magnitude of the resultant vector is bardbl vector F bardbl = radicalBig F 2 x + F 2 y = radicalBig ( − 21 . 1518 N) 2 + ( − 16 . 1635 N) 2 = 26 . 6206 N . 002 (part 2 of 2) 10.0 points What is the direction of this resultant vec- tor vector F , within the limits of − 180 ◦ and 180 ◦ as measured from the positive x axis with coun- terclockwise positive ?...
View Full Document

## This note was uploaded on 10/31/2010 for the course PHYSICS 1710 taught by Professor Weathers during the Fall '10 term at North Texas.

### Page1 / 5

solution7_pdf - arellano(aa39398 – Homework 4 –...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online