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Unformatted text preview: arellano (aa39398) – Homework 9 – weathers – (17101) 1 This printout should have 11 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points A force vector F = F x ˆ ı + F y ˆ acts on a particle that undergoes a displacement of vectors = s x ˆ ı + s y ˆ where F x = 6 N, F y = − 3 N, s x = 4 m, and s y = 2 m. Find the work done by the force on the particle. Correct answer: 18 J. Explanation: The work is given by W = vector F · vectors = F x s x + F y s y = (6 N) (4 m) + ( − 3 N) (2 m) = 18 J . 002 (part 2 of 2) 10.0 points Find the angle between vector F and vectors . Correct answer: 53 . 1301 ◦ . Explanation: Since W = vector F · vectors = vextendsingle vextendsingle vextendsingle vector F vextendsingle vextendsingle vextendsingle  vectors  cos θ θ = cos − 1 W vextendsingle vextendsingle vextendsingle vector F vextendsingle vextendsingle vextendsingle  vectors  . vextendsingle vextendsingle vextendsingle vector F vextendsingle vextendsingle vextendsingle = radicalBig F 2 x + F 2 y = radicalBig (6 N) 2 + ( − 3 N) 2 = 6 . 7082 N and  vectors  = radicalBig s 2 x + s 2 y = radicalbig 4 m 2 + 2 m 2 = 4 . 47214 m , so θ = cos − 1 bracketleftbigg 18 J (6 . 7082 N) (4 . 47214 m) bracketrightbigg = 53 . 1301 ◦ . 003 10.0 points A shopper in a supermarket pushes a cart with a force of 37 . 6 N directed at an angle of 24 . 5 ◦ downward from the horizontal. Find the work done by the shopper as she moves down a 50 . 8 m length of aisle....
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This note was uploaded on 10/31/2010 for the course PHYSICS 1710 taught by Professor Weathers during the Fall '10 term at North Texas.
 Fall '10
 Weathers
 Force, Work

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