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# solution21_pdf - arellano(aa39398 Practice Homework Chapter...

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arellano (aa39398) – Practice Homework Chapter 6 Solutions – weathers – (17101) 2 4. F = m ω 2 r 2 + m g 5. F = m g Explanation: According to the explanation in the previ- ous part, the minimum adhesion force is bardbl vector G bardbl + bardbl vector F c bardbl = m ω 2 r + m g . 004 (part 1 of 2) 10.0 points A spring has a force constant of 761 N / m and an unstretched length of 8 cm. One end is attached to a post that is free to rotate in the center of a smooth table, as shown in the top view below. The other end is attached to a 4 kg disk moving in uniform circular motion on the table, which stretches the spring by 1 cm.
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