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Unformatted text preview: arellano (aa39398) Practice Homework Chapter 6 Solutions weathers (17101) 1 This printout should have 43 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points A fighter plane flying at constant speed 540 m / s and constant altitude 12000 m makes a turn of curvature radius 5700 m. On the ground, the planes pilot weighs (79 kg) (9 . 8 m / s 2 ) = 774 . 2 N. What is his/her apparent weight during the planes turn? Correct answer: 4114 . 96 N. Explanation: The planes altitude is not important per se , but the fact that it is constant tells us that the plane moves in a horizontal plane and its normal acceleration a N = v 2 R = 51 . 1579 m / s 2 has a horizontal direction. Furthermore, con stant speed implies zero tangential accelera tion, hence vectora = vectora N . The apparent weight of the pilot combines his true weight mvectorg and the inertial force mvectora due to planes acceleration, vector W app = m ( vectorg vectora ) . In magnitude,  vectorg vectora  = radicalbig g 2 + a 2 = 52 . 0881 m / s 2 because vectora is horizontal while vectorg is vertical. Consequently, the pilots apparent weight is vector W app = (52 . 0881 m / s 2 ) (79 kg) = 4114 . 96 N , which is quite heavier than his/her true weight of 774 . 2 N. 002 (part 1 of 2) 10.0 points An ant of mass m clings to the rim of a flywheel of radius r , as shown. The flywheel rotates clockwise on a horizontal shaft S with constant angular velocity . As the wheel rotates, the ant revolves past the stationary points I , II , III , and IV . The ant can adhere to the wheel with a force much greater than its own weight. r S I II III IV Ant It will be most difficult for the ant to adhere to the wheel as it revolves past which of the four points? 1. IV 2. II 3. III correct 4. It will be equally difficult for the ant to adhere to the wheel at all points. 5. I Explanation: The sum of the ants gravity and its ad hesion force is the centripetal force vector F c with magnitude m 2 r . Thus vector F c = mvectorg + vector F ad vector F ad = vector F c mvectorg . The maximum vector F ad is when vector F c and mvectorg are in opposite directions; i.e. , at III . 003 (part 2 of 2) 10.0 points What is the magnitude of the minimum adhe sion force necessary for the ant to stay on the flywheel at point III ? 1. F = m 2 r + mg correct 2. F = m 2 r 2 3. F = m 2 r mg arellano (aa39398) Practice Homework Chapter 6 Solutions weathers (17101) 2 4. F = m 2 r 2 + mg 5. F = mg Explanation: According to the explanation in the previ ous part, the minimum adhesion force is bardbl vector G bardbl + bardbl vector F c bardbl = m 2 r + mg ....
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This note was uploaded on 10/31/2010 for the course PHYSICS 1710 taught by Professor Weathers during the Fall '10 term at North Texas.
 Fall '10
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