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Unformatted text preview: STRUCTURAL STRUCTURAL ANALYSIS ANALYSIS Method of Sections Method of Sections LEARNING OBJECTIVES LEARNING OBJECTIVES Be able to determine the forces in Be able to determine the forces in members of a simple truss using the members of a simple truss using the method of sections method of sections PREREQUISITE KNOWLEDGE PREREQUISITE KNOWLEDGE Units of measurement Units of measurement Trigonometry concepts Trigonometry concepts Rectangular component concepts Rectangular component concepts Equilibrium of forces in 2D Equilibrium of forces in 2D METHOD OF SECTIONS In this method, a truss is divided into sections; the equilibrium equations are applied at the division line considering both external and member forces. The division line does not have to be linear but has to pass through the members where the solution of the forces is desired. Determine the forces in members BC, GC and GF EXAMPLE 1 SOLUTION 1 Use the method of sections through aa to pass members BC, GC and GF : SOLUTION 1 ∑ F Y = 0; F GC sin 45 o – 1000 = 0, F GC = 1414 N (T) ∑ M G = 0; 1000(2) – F BC (2) = 0, F BC = 1000 N (T) on) (compressi N 2000 F F cos45 F F ; F GF GF GC BC X = =+ = ∑ o EXAMPLE 2 Determine the forces in member EB of the roof truss. SOLUTION 2 ∑ M B = 0; 1000(4) + 3000(2) – 4000(4) + F ED Sin30°(4) = 0 F ED = 3000 N (C) SOLUTION 2 continued ∑ F X = 0; F EF Cos30°  3000Cos30° = 0; F = 3000 N (C) EXAMPLE 3...
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This note was uploaded on 10/31/2010 for the course CEE CE 221 taught by Professor Baladi during the Fall '10 term at Michigan State University.
 Fall '10
 Baladi

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