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Unformatted text preview: angles. Therefore, AP ←-→ and BP ←-→ are tangent to the circle with center O by Theorem (NIB) 4.4 . Q E D A B M O P O P Construction (NIB): Given two points P and Q, construct the set of all centers of circles which contain both P and Q . Solution: Construct the perpendicular bisector of the segment . Given: Construct: Construction (NIB): Given a line m and a point P on line m, construct the set of the centers of all of the circles to which line m is a tangent line with point of tangency at point P . Solution: Construct the line through P which is perpendicular to line m . Given: Construct: Q P m P m P Q P O 1 O 2 O 3 Construction (NIB): Given a line m which contains point P and given another point Q, with Q not on line m, construct a circle passing through Q and tangent to line m at point of tangency P. Given: Construct: Q m P Z Q m P...
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- Spring '10
- Construct lines AP