This preview shows page 1. Sign up to view the full content.
Unformatted text preview: through P. Proof: Let l be any line and let P be a point not on line l . By the "Drop a Perpendicular" Theorem, there is a unique line t such that t passes through P and l t . By the "Drop a Perpendicular" Theorem, there is unique line m such that m passes through P and t m . Therefore, l and m share the common perpendicular t . Q E D P l t P l m t P l...
View
Full
Document
This note was uploaded on 11/02/2010 for the course MATH modern geo taught by Professor Shirley during the Spring '10 term at University of Texas at Austin.
 Spring '10
 Shirley

Click to edit the document details