This preview shows page 1. Sign up to view the full content.
Unformatted text preview: through P. Proof: Let l be any line and let P be a point not on line l . By the "Drop a Perpendicular" Theorem, there is a unique line t such that t passes through P and l t . By the "Drop a Perpendicular" Theorem, there is unique line m such that m passes through P and t m . Therefore, l and m share the common perpendicular t . Q E D P l t P l m t P l...
View Full Document
This note was uploaded on 11/02/2010 for the course MATH modern geo taught by Professor Shirley during the Spring '10 term at University of Texas at Austin.
- Spring '10