This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Homework 5 Solutions Math 332, Spring 2010 Problem 1. Proposition. Let G be the following subgroup of GL (2 , R ) : G = a b b a : a,b ∈ R and ( a,b ) 6 = (0 , 0) . Then G is isomorphic to C # , the group of nonzero complex numbers under multiplication. Proof. Define ϕ : C # → G by ϕ ( a + bi ) = a b b a . Clearly ϕ is a bijection. Furthermore, if a + bi,c + di ∈ C # , then ϕ ( ( a + bi )( c + di ) ) = ϕ ( ( ac bd ) + ( ad + bc ) i ) = ac bd ad bc ad + bc ac bd = a b b a c d d c = ϕ ( a + bi ) ϕ ( c + di ) , and therefore ϕ is an isomorphism. Problem 2. Proposition. Let Aff ( R ) be the group of all functions f : R → R of the form f ( x ) = ax + b where a,b ∈ R and a 6 = 0 . Then Aff ( R ) is isomorphic to the group G = a b 0 1 : a,b ∈ R and a 6 = 0 . Proof. Let ϕ : Aff ( R ) → G be the function that maps f ( x ) = ax + b to the matrix a b 0 1 . Clearly ϕ is a bijection. To prove that ϕ is an isomorphism, let f,g ∈ Aff ( R ), where f ( x ) = ax + b and...
View
Full Document
 Spring '09
 Algebra, Multiplication, Complex Numbers, following table, ad + bc, nonzero complex numbers, Element Representation, −b ba ac

Click to edit the document details