CHM111-practiceexam1

CHM111-practiceexam1 - Practice Exam #1 Name _ Read...

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Practice Exam #1 Name ___________________ Read instructions carefully and follow them. Show calculations to receive maximum credit. Significant figures should be correct. Formulas and constants: c = v λ E = hv = h c E = 2 k 2 e 4 π 2 m n 2 h 2 r = n 2 h 2 4 ke 2 2 m = h m v Δ ( m v ) ⋅ Δ x h 4 h = 6.63 x 10 -34 J s c = 3.00 x 10 8 m s -1 k = 8.99 x 10 9 J m C -2 m e = 9.11 x 10 -31 kg e = 1.60 x 10 -19 Avogadro’s number = 6.02 x 10 23 atoms mol -1
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1) Answer the following questions regarding these atoms: a) Complete the table: Element # protons # neutrons # electrons Electron configuration 69 Ga 71 Ga +3 10 B b) Which is larger, Ga +3 or Ga? State the trend that this exemplifies and explain it. c) Which element requires less energy to form a positive ion, Ga or B? State the trend that this exemplifies and explain it.
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2) In different solar systems, the relative abundances of the elements can be different than those on Earth, affecting the atomic weight of an element. a)
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This note was uploaded on 10/30/2010 for the course CHM 111 taught by Professor Stanitski during the Fall '08 term at F & M.

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CHM111-practiceexam1 - Practice Exam #1 Name _ Read...

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