hw3_solution

# hw3_solution - 1 Homework 3 Solution 8.9 Twenty-four voice...

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1 Homework 3 Solution 8.9 Twenty-four voice signals are to be multiplexed and transmitted over twisted pair. What is the bandwidth required for FDM? Assuming a bandwidth efﬁciency (ratio of data rate to transmission bandwidth, as explained in Chapter 5) of 1 bps/Hz, what is the bandwidth required for TDM using PCM? A: Assuming 4 kHz per voice signal, the required bandwidth for FDM is 24 × 4 = 96 kHz. With PCM, each voice signal requires a data rate of 64 kbps, for a total data rate of 24 × 64 = 1 . 536 Mbps. At 1 bps/Hz, this requires a bandwidth of 1.536 MHz. 8.13 Ten 9600-bps lines are to be multiplexed using TDM. Ignoring overhead bits in the TDM frame, what is the total capacity required for synchronous TDM? Assuming that we wish to limit average link utilization of 0.8, and assuming that each link is busy 50% of the time, what is the capacity required for statistical TDM? A: Synchronous TDM: 9600 bps × 10 = 96 kbps Statistical TDM: 9600 bps × 10 × 0 . 5 / 0 . 8 = 60 kbps 9.7 Figure 1 depicts a simpliﬁed scheme for CDMA encoding and decoding. There are seven logical channels,

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hw3_solution - 1 Homework 3 Solution 8.9 Twenty-four voice...

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