solutio234n2_pdf - kinsey (cbk323) oldhomework 02 Turner...

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Unformatted text preview: kinsey (cbk323) oldhomework 02 Turner (56725) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points The diagrams below depict three electric field patterns. Some of these patterns are physi- cally impossible. Assume these electric field patterns are due to static electric charges outside the regions shown. (a) (b) (c) Which electrostatic field patterns are phys- ically possible? 1. (a) and (b) 2. (b) and (c) 3. (b) only correct 4. (a) and (c) 5. (a) only 6. (c) only Explanation: Electrostatic lines of force do not intersect one another. Neither do they form a closed circuit (unless there is a changing magnetic field present). 002 (part 1 of 2) 10.0 points Three charges are arranged as shown in the figure. x y 2 . 3 nC 3 . 7 m . 9 nC . 48 nC 1 . 5 m Find the magnitude of the electro- static force on the charge at the origin. The Coulomb cosnstant is 8 . 98755 10 9 N m 2 / C 2 . Correct answer: 2 . 19648 nN. Explanation: Let : ( x ,y ) = (0 m , 0 m) , q = . 9 nC , ( x 1 ,y 1 ) = (3 . 7 m , 0 m) , q 1 = 2 . 3 nC , ( x 2 ,y 2 ) = (0 m , 1 . 5 m) , and q 2 = 0 . 48 nC . x y q 1 x 1 q q 2 y 2 F The force vector F 10 (in the hatwider 10 direction, ) be- tween charge 9 10 10 C and 2 . 3 10 9 C is vector F 10 = + k e q q 1 x 2 1 ( ) = ( 8 . 98755 10 9 N m 2 / C 2 ) kinsey (cbk323) oldhomework 02 Turner (56725) 2 ( . 9 nC) (2 . 3 nC) (3 . 7 m) 2 = (1 . 35897 10 9 N) . The plus sign means the force vector F 10 is towards the positive x-axis. The force vector F 20 (in the hatwider 20 direction, + ) between charge 9 10 10 C and 4 . 8 10 10 C is vector F 20 = + k e q q 2 y 2 2 (+ ) = (8 . 98755 10 9 N m 2 / C 2 ) ( . 9 nC) (0 . 48 nC) ( 1 . 5 m) 2 = ( 1 . 72561 10 9 N) . The minus sign means the force vector F 20 is towards the negative y-axis. The magni- tude of the total force exerted on the charge 9 10 10 C is equal to bardbl vector F bardbl = radicalBig F 2 10 + F 2 20 = bracketleftBig (1 . 35897 10 9 N) 2 + ( 1 . 72561 10 9 N) 2 bracketrightBig 1 2 = 2 . 19648 10 9 N = 2 . 19648 nN ....
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solutio234n2_pdf - kinsey (cbk323) oldhomework 02 Turner...

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