Test 3 solution

Test 3 solution - Equation of plane is ax by cz ax 0 by 0...

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Equation of plane is 0 0 0 ax by cz 2 3 1 yz   since ( , , ) (0,1,1) abc as evidenced by the normal vector n . For parametric representation of the plane, we take , 1 x u y v z v    , The vector equation describing the plane would be ( , ) , 1 u v u v v   r Alternatively , realizing that any vector in the plane containing the two given (non co- linear) vectors 1,1, 1 and 1, 1,1  can be written as a linear combination of these two vectors (Parallelogram Law),
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This note was uploaded on 11/04/2010 for the course MATH 17100 taught by Professor Kitchens during the Spring '10 term at IUPUI.

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Test 3 solution - Equation of plane is ax by cz ax 0 by 0...

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