47134_HW7 - ragsdale(zdr82 HW7 ditmire(58335 This print-out should have 28 questions Multiple-choice questions may continue on the next column or

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ragsdale (zdr82) – HW7 – ditmire – (58335) 1 This print-out should have 28 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points A wire carrying a current 30 A has a length 0 . 1 m between the pole Faces oF a magnet at an angle 60 (see the fgure). The magnetic feld is approximately uniForm at 0 . 5 T. We ignore the feld beyond the pole pieces. ( θ I B What is the Force on the wire? Correct answer: 1 . 29904 N. Explanation: Let : I = 30 A , ( =0 . 1m , θ = 60 , and B . 5T . we use F = I ( B sin θ , so F = I ( B sin θ = (30 A) (0 . 1 m) (0 . 5 T) sin60 = 1 . 29904 N . 002 10.0 points The magnetic Force on a straight 0.45 m seg- ment oF wire carrying a current oF 4.5 A is 0.31 N. What is the magnitude oF the component oF the magnetic feld that is perpendicular to the wire? Correct answer: 0 . 153086 T. Explanation: Let : ( . 45 m , I =4 . 5A , and F m . 31 N . The magnetic Force is F m = I ( B B = F m I ( = 0 . 31 N (4 . 5 A) (0 . 45 m) = 0 . 153086 T 003 10.0 points A rectangular loop oF wire hangs vertically as shown in the fgure. A magnetic feld is di- rected horizontally, perpendicular to the wire, and points out oF the page at all points as rep- resented by the symbol ± . The magnetic feld is very nearly uniForm along the horizontal portion oF the wire ab (length is 0 . 1 m) which is near the center oF a large magnet produc- ing the feld. The top portion oF the wire loop is Free oF the feld. The loop hangs From a balance which measures a downward Force (in addition to the gravitational Force) oF 3 × 10 - 2 N when the wire carries a current 0 . 2 A. a b II F ( B What is the magnitude oF the magnet feld B at the center oF the magnet? Correct answer: 1 . 5 T. Explanation: Let : F =3 × 10 - 2 , ( . , and I . 2A .
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ragsdale (zdr82) – HW7 – ditmire – (58335) 2 The magnetic forces on the two vertical sec- tions of the wire loop point to the left and right, respectively. They are equal but in opposite directions, so they add up to zero. Thus the net magnetic force on the loop is that on the horizontal section ab whose length is ( =0 . 1 m (and θ = 90 so sin θ = 1), and B = F I ( = 3 × 10 - 2 N (0 . 2 A) (0 . 1 m) = 1 . 5T . 004 (part 1 of 4) 10.0 points Two wires each carry a current I in the xy plane and are subjected to an external uni- form magnetic Feld ) B , which is directed along the positive y axis as shown in the Fgure. R I wire #2 I wire #1 B L L x y What is the magnitude of the force on wire #1 due to the external ) B Feld? 1. ± ) B ± = (2 L + R ) IB 2. ± ) B ± = I 2 (2 L +2 R ) B 3. ± ) B ± = ± L + R 2 ² 4. ± ) B ± =2 I R L B 5. ± ) B ± = I ( L + R ) B 6. ± ) B ± I ( L + R ) B correct 7. ± ) B ± I L B 8. ± ) B ± =4 I ( L + R ) B 9. ± ) B ± = (2 BL R ) I 10. ± ) B ± I R B Explanation: ) F = I ³ d)s × ) B = I ) ( × ) B. ±or wire 1, ) ( ) B, so the magnitude of ) F is just F = I ( B . ±or wire #1, ( L R. Thus F = 2 I ( R + L ) B . 005 (part 2 of 4) 10.0 points What is the magnitude of the force on the curved part of wire #2 due to the external magnetic Feld?
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This note was uploaded on 11/03/2010 for the course PHYSICS 303 taught by Professor Shih during the Spring '10 term at University of Texas at Austin.

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47134_HW7 - ragsdale(zdr82 HW7 ditmire(58335 This print-out should have 28 questions Multiple-choice questions may continue on the next column or

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