{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW8 - Version One – Homework 8 – Savrasov – 39819 –...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Version One – Homework 8 – Savrasov – 39819 – May 15, 2006 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Magnetic Field from an Arc 01 30:01, calculus, multiple choice, > 1 min, wording-variable. 001 (part 1 of 2) 1 points Consider two radial legs extending to infin- ity and a circular arc carrying a current I as shown below. x y I I I I 20 23 π O r What is the magnitude of the magnetic field B at the origin O due to the current through this path? 1. B = 5 23 μ I r correct 2. B = 5 23 μ I r 2 3. B = 5 23 μ I π r 4. B = 5 23 μ I π r 2 5. B = 5 23 μ I π 6. B = 2 23 μ I r 7. B = 2 23 μ I r 2 8. B = 2 23 μ I π r 9. B = 2 23 μ I π r 2 10. B = 2 23 μ I π Explanation: Using the Biot-Savart law, the magnetic field due to the two radial legs is zero since d s × ˆ r = 0 . However, around the arc | d s × ˆ r | = ds = r dθ . The magnetic field at the center of an arc with a current I is B = μ I 4 π d s × ˆ r r 2 = μ I 4 π r 2 ds = μ I 4 π r 2 r dθ = μ I 4 π r 20 23 π dθ = μ I 4 π r θ 20 23 π = μ I 4 π r 20 23 π- = 5 23 μ I r . 002 (part 2 of 2) 1 points What is the direction of the magnetic field B at point O due to the current through the path? 1. B is out of the page. correct 2. B is into the page. 3. B is to the right. 4. B is to the left. 5. B is down the page. 6. B is up the page. 7. B is zero. Explanation: The right-hand rule dictates that magnetic field is out of the page. Version One – Homework 8 – Savrasov – 39819 – May 15, 2006 2 Square Loop of Wire 01 30:01, calculus, multiple choice, > 1 min, wording-variable. 003 (part 1 of 3) 1 points A conductor in the shape of a square of edge length carries a counter-clockwise current I as shown in the figure below. I P What is the magnitude of the magnetic field at point P (at the center of the square loop) due to the current in only one of the sides of the wire? 1. B = μ I 2 π √ 2 correct 2. B = μ I 3 π √ 2 3. B = μ I 2 π 4. B = μ I π √ 2 5. B = μ I √ 2 6. B = μ I 2 √ 2 π 7. B = μ I π 2 √ 2 8. B = 2 μ I π 9. B = μ I √ 2 3 10. B = μ I 2 Explanation: By the Biot-Savart law, dB = μ 4 π I d s × ˆ r r 2 ....
View Full Document

{[ snackBarMessage ]}

Page1 / 6

HW8 - Version One – Homework 8 – Savrasov – 39819 –...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon bookmark
Ask a homework question - tutors are online