pbs11key - Problem Set 11 Answers 1. The mechanism is just...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Problem Set 11 Answers 1. The mechanism is just like pyruvate DH, except the substrate is bigger: 2. Labeled [1- 14 C]-glucose: a. glyceraldehyde 3-phosphate is labeled in the C3 position, where the OPi is attached). b. acetyl-CoA is labeled in the C2 position: the methyl group. c. α -ketoglutarate is labeled in the C4 position (the CH 2 that is between the other CH 2 and the COO-). d. oxaloacetate is labeled equally distributed in the C2 and C3 positions: remember that succinate is symmetric, and thus the label gets randomized from this point forward. 3. Getting all of the 14 C as CO 2 takes essentially an infinite number of cycles. On cycle 2, you release none of the 14 C, yet, but you do move it one step closer (except that the symmetric succinate once again “moves” some of it up so that it will not get released on the next cycle). On cycle 3, you finally remove some 14 C, but only the part that didn’t get turned around by the symmetric succinate shuffle. Thus, it takes many many cycles to remove all the
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

pbs11key - Problem Set 11 Answers 1. The mechanism is just...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online