Unformatted text preview: Jessica has one son, who has disease Y. In the absence of other information, the probability is 0.32 that the son is the victim of a spontaneous mutation and 0.68 that Jessica is a carrier. There is a screening test called the CK test that is positive with probability 0.75 if a woman is a carrier and with probability 0.15 is she is not. Jessica’s CK test is positive. Find the conditional probability that Jessica is a carrier given that her CK test is positive. Round your final answer to four decimal places if necessary....
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This note was uploaded on 11/07/2010 for the course PAM 2100 taught by Professor Abdus,s. during the Spring '08 term at Cornell.
- Spring '08