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Unformatted text preview: 1 / 2 ⋅− 1 n 1 . The sum is obtained by subtracting the first term 2 n from what the missing term after the final term would be (i.e., from 1 / 2 ⋅− 1 n 1 , finally dividing by (common ratio  1), i.e. dividing by − 3 / 2 = − 1 / 2 − 1: S = 1 / 2 ⋅− 1 n 1 − 2 n − 3 / 2 = 2 n 1 − 1 n 3 ....
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This note was uploaded on 11/01/2010 for the course INFS 501 taught by Professor Ellis,w during the Spring '08 term at George Mason.
 Spring '08
 Ellis,W

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