www.michaelpready.com - Spring 2009 Exam 3

www.michaelpready.com - Spring 2009 Exam 3 - Exam 3 Answer...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Exam 3 Answer the following. Physical constants and a table of standard reduction potentials are located on the last page of the test. Graph paper is attached. Assume all temperatures are 37 o C . There are 103 points on this test. Good Luck. 1) Ascorbic acid (Vitamin C, below) acts as an antioxidant in vivo, helping protect the body against oxidizing. mutation-inducing chemical agents as well as against radiation. Oxidized ascorbate (dehydroascorbate) isnt much use, however. Plants can use NADPH to reduce the oxidized form of ascorbate (dehydroascorbate) back to ascorbic acid as shown in the reaction below: Dehydroascorbate + NADPH + H + Ascorbate + NADP + What is the equilibrium constant for this reaction? (Standard reduction potentials are on the last page) (6 pts) 2) The Krebs cycle produces both NADH and FADH 2 . Both transfer their electrons to the electron transport chain and becomes reoxidized. Each NADH produced in the Krebs cycle results in the production of (optimally) about 2.5 - 3 ATPs, while each FADH 2 produced in glycolysis only results in (optimally) about 1.5 - 2 ATPs. Explain why this is true. (5 pts) Electrons from FADH...
View Full Document

Page1 / 6

www.michaelpready.com - Spring 2009 Exam 3 - Exam 3 Answer...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online