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Problem Set 1 for S08_Solutions

Problem Set 1 for S08_Solutions - Problem Set 1 Page 1 of 7...

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CH 339K Problem Set 1 1) Dihydroxyacetone phosphate (DHAP)and Glyceraldehyde-3-Phosphate (G3P) are both intermediates in the metabolic breakdown of glucose. They can be interconverted by the enzyme Triose Phosphate Isomerase . For the conversion of DHAP to G3P, G o = 7.5 kJ/mol a) Calculate Keq and the equilibrium fraction of G3P at 37 o C. b) What is G if [G3P] = 1/100 [DHAP]? 2) A Cl - ion is separated from a Na + ion by a distance of 0.5 nm. What is the interaction energy (in Joules/mole) in a. Water ( ε = 78.54) DHAP G3P % 2 . 5 052 . ] 3 [ 0545 . ] 3 [ 0545 . 1 ] 3 [ 0545 . 0545 . ] 3 [ 0545 . ] 3 [ 1 ] 3 [ 0545 . ] [ ] 3 [ 0545 . 0 91 . 2 ) 310 )( / 315 . 8 ( / 7500 ' 0 = = = - = = - = = = = = - - - P G P G P G P G P G P G DHAP P G K e K e K e K eq eq K Kmol J mol J eq RT G eq mol J mol J mol J G K Kmol J mol J G RT G G ts reac products RT G G / 4371 ) / 11871 ( / 7500 )) 01 )(ln(. 310 )( / 315 . 8 ( / 7500 100 1 ln ] tan [ ] [ ln ' 0 ' 0 - = - + = + = + = + = Page 1 of 7 Problem Set 1 1/26/2010 http://www.michaelpready.com/mready/ProblemSet1forS08_Solutions.htm
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b. n-Pentane ( ε = 1.84) The Point: electrostatic interactions are stronger in environments with lower dielectric constants (like, say, organic solvents or the hydrophobic interiors of macromolecules.) 3) What is the pH of each of the following unbuffered solutions? a. 0.35 M HCl HCl is a strong acid, so it dissociates completely to (formally speaking) H + and Cl - . pH = -log[H + ] = -log(0.35) = 0.456 b. 0.35 M Acetic Acid HAc is a weak acid: we can solve using the quadratic equation: or the approximation: c. 0.035 M Acetic Acid ( 29( 29 ( 29 ( 29 1 2 19 19 9 2 23 1 10 1 1.602 10 1.602 10 (8.99 10 ) 6.023 10 78.54 5 10 3538 q q U k r C C U JmC mol m U Jmol ε - - - - - - = + - = = - ( 29( 29 ( 29 ( 29 1 2 19 19 9 2 23 1 10 1 1.602 10 1.602 10 (8.99 10 ) 6.023 10 1.84 5 10 151 q q U k r
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