{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HWK 3 solution - torque at a given rotating speed The top...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
PGE 203 HWK 3 Solution Due at start of lecture: Feb. 22 The hoist that raises pipe out of a well or lowers pipe into a well is called the draw works. The power that a draw works must have is related to the weight being picked up and the speed at which the pipe is raised or lowered. (1) Compute the weight suspended from the derrick if the pipe weighs 26 lbf/ft and the length of pipe in the well is 20,000 ft and the drilling mud in the well has a density of 16 lbm/gal. ( 29 ( 29 ( 29 f 26 20,000 1 0.0153 16 392,704 lb W = - = (2) Assuming the draw works can raise pipe 90 ft in one minute and that the total pipe weight is 1,000,000 lbf, what is the horsepower requirement for the draw works? Recall that Hp x 33,000 = lbf-ft/min. ( 29 f f 1,000,000 90 lb ft hp-min 2,727 hp 33,000 min lb ft P = = Torque is required to overcome friction in the well and cause the bit to turn at the bottom of the drill string. A machine called a top drive provides the power necessary to create the
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: torque at a given rotating speed. The top drive is suspended in the derrick and connected directly to the top of the drill pipe. (3) What is the maximum torque a 375 KW top drive can produce at 125 revolutions/minute (recall that there are 2π radians/revolution)? Please show the torque in units of ft-lbf. ( 29 f f f f hp 375 KW 502 hp 0.7457 KW lb ft lb ft 502 hp 33,000 16,566,000 min min lb ft rev min 16,566,000 21,093 ft-lb min 2 radians 125 rev P P T π = = = = = = The mud pumps are required to circulate drilling mud from the surface through the inside of the drill string and back to the surface in the annulus between the hole and the outside of the drill pipe. (4) A pump is required to circulate mud at 150 gal/min with a pressure of 5,000 psi. What is the hydraulic horsepower of the pump? 3 2 f 2 2 f 5,000 lb 150 gal ft 144 in min hp min 7.48 gal 33,000 lb ft in ft 438 hp P P = =...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern