phys 369 09 hw 10 Solutions

# phys 369 09 hw 10 Solutions - Phys 369 Fall 2009...

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1 Phys. 369, Fall 2009 Homework #10 Solutions 1. (22 points) The relevant part of the solution to problem 3.25 is:

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3 (Aside to TA: students are only responsible for the part of this solution that answers the questions posed in problem 6.20.) 2. (14 points)

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4 3. (16 points) 4. (24 points)
5 5. (24 points) a) According to Matweb.com, the thermal conductivity of 303 Stainless steel is k t = 16.2 W/m K at 100 ° C. The thermal conductivity is not a strong function of temperature, so I’ll assume that k t = 16.2 W/m K over the range from 20 to 40 ° C as well. Then it follows that the rate of heat conduction down the rod is () 2 3 W 16.2 2.5 10 m m K 20 K 0.0127 W 0.5 m t kA dQ T dt π ×× = = A

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6 where A is the cross-sectional area of the rod, with radius 3 diameter/2 2.5 10 m r == × , 0.5 m = A is the length of the rod, and ( ) 40 C 20 C 20 K T Δ= °− ° = is the difference in temperature between the ends of the rod. b) According to Matweb.com, the specific heat capacity of stainless steel is
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phys 369 09 hw 10 Solutions - Phys 369 Fall 2009...

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