hw 33 - ECE 201 Spring 2010 Homework 33 Solutions Problem...

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Unformatted text preview: ECE 201 Spring 2010 Homework 33 Solutions Problem 30 (a) 1 1 + R jωL j 0.25 = 0.05 − ω 1 Zin (jω ) = Yin (jω ) j 20ω = 5 + jω Yin (jω ) = (b) IL = Iin Zin (jω ) jωL 10(i + j ) = 10 × j 20 √ −jπ/4 = 5 2e ⇒ iL (t) = 10 cos(5t − π/4) mA Problem 40 Let the impedances of R1 , C and R2 , L combinations be Z1 and Z2 respectively. Z1 = 1 + j (400 × 5 × 10−6 ) 500 = 250(1 − j ) −1 Z2 1 1 + = 100 j (400 × 0.125) = 20(1 + 2j ) −1 1 Let the phasor current through the source be I. I= ⇒ VC = = ⇒ vC (t) = IL = = = ⇒ iL (t) = V 270 − j 210 I × 250(1 − j ) 120 √ (1.0256 − j 0.1282) 2 124.032 cos(400t − 7.125◦ ) V R2 V 270 − j 210 R2 + jωL V × 100 (270 − j 210)(100 + j 50) 240 √ (0.00128205 + j 0.0002564) 2 0.3138 cos(400t + 11.3099◦) A 2 ...
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This note was uploaded on 11/06/2010 for the course ECE 201 taught by Professor All during the Spring '08 term at Purdue University-West Lafayette.

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hw 33 - ECE 201 Spring 2010 Homework 33 Solutions Problem...

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