hw 40 - ECE 201 Spring 2010 Homework 40 Solutions Problem...

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ECE 201 Spring 2010 Homework 40 Solutions Problem 30 (a) Z th = ( R 1 || R 2 ) - j/ωC = (20 - j 10) Ω V oc = V s R 2 R 1 + R 2 = 20 V rms For maximum power transfer, Z L = Z * th = (20 + j 10) Ω. (b) P avg = V 2 oc 4 R L = 5 W Problem 37 (a) Here we cannot apply the maximum power transfer theorem because R L is ±xed. The expression for average power across R L is given by P avg = V 2 s R L ( R + R L ) 2 + ( ωL - 1 /ωC ) 2 Clearly, the average power is maximum when the denominator is minimum,
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This note was uploaded on 11/06/2010 for the course ECE 201 taught by Professor All during the Spring '08 term at Purdue University.

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hw 40 - ECE 201 Spring 2010 Homework 40 Solutions Problem...

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