calc 1 exam

calc 1 exam - 1.0 < | x c | < 2.| f(x) L | < lim 3x - 3 =...

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1.0 < | x – c | < δ 2.| f(x) – L | < ε lim 3x - 3 = 12 x~5 1.0 < | x - 5 | < δ 2. | ( 3x - 3 ) - 12 | < ε simplify then par (2) | (x - 5) | < ε/3 CHOOSE δ = ε/3 1.0 < | x - 5 | < ε/3 2. | f(x) - L | < ε | 3x - 15 | < ε | x - 5 | < ε/3
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This note was uploaded on 11/06/2010 for the course CALC 104 taught by Professor Yin during the Spring '08 term at NJIT.

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