chapter24 - 1 =-70 V and V 2 =-50V. The particle is slowing...

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Q1: What is the net electric potential at point P due to the four particles if q=5 nC and d=4 cm. Q2: The thin plastic rod of length L in figure has a nonuniform linear charge density cx , where c is constant. With V = 0 at infinity, find the electric potential at point P on the y axis at distance D.
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Q3 : In figure, three thin plastic rods form quarter-circles with a common center of curvature at the origin. The uniform charges on the rods are Q 1 = 30 nC, Q 2 = +3Q 1 and Q 3 = -8Q 1 . What is the net electric potential at origin due to the rods? Q4 : For the given system in figure; a) How much work is required to set-up the arrangement if q=2 nC and a=6 cm. b) How much work is needed to place a 2q charge to the center of the arrangement?
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Q5 : In figure, a charged particle (either an electron or a proton) is moving rightward between two parallel charged plates separated by distance d=2 mm. The plate potentials are V
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Unformatted text preview: 1 =-70 V and V 2 =-50V. The particle is slowing from initial speed of 90 km/s at the left plate. a) Is the particle an electron or a proton? b) What is its speed just as it reaches plate 2? Q6 : In figure, point P is at distance d 1 =4 m from particle 1 (q 1 =-2e) and distance d 2 =2 m from particle 2 (q 2 = +2e), with both particles fixed in place. a) With V=0 at infinity, what is the potential at P? b) If we bring a particle of charge q 3 =+2e from infinity to point P (i) How much work do we do? (ii) What is the potential energy of the three-particle system? Q7: Over a certain region of space, the electric potential is V = 5x – 3x 2 y + 2yz 2 . Find the expressions for the x, y, and z components of the electric field over this region. What is the magnitude of the field at the point P, which has coordinates (1, 0, -2) m?...
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This note was uploaded on 11/07/2010 for the course COMPUTER 223-231-25 taught by Professor Mcbulut during the Spring '10 term at A.T. Still University.

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chapter24 - 1 =-70 V and V 2 =-50V. The particle is slowing...

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